Manufacturers list a motor's maximum amp draw and voltage for a given kv value. The lower the kv value the lower the amp draw at the expense of a higher voltage used. This is useful in determining a suitable capacity ESC. However, what I cannot understand is not everyone runs at the max voltage listed by the manufacturer, thus if max power is wanted then obviously the amp draw would increase. If however, a lower voltage and suitably smaller prop were chosen, would the user exceed the max current draw listed on the motor specifications?
When would one be drawing the full wattage (power) of the motor - using too high a kv to maximise rpm or using too large a diameter prop? How does one select a suitable esc when a manufacturer lists a lower numerical amperage draw against a max voltage that most would never consider? Does a lower amp draw/higher voltage low kv motor differ in construction (wire diameter,number of windings) to a higher kv motor or is it simply that a lower voltage implies a higher amp draw for a given wattage output?
If one chooses to use 6s packs then the specification amp draw places one with the choice of a minimum 180 amp esc and most likely higher, say a 200, 220 or 240 amp unit. A manufacturer will use the amp draw as simply a product of wattage and voltage, however how does one know what his final amp draw is going to be (other than by failure of the esc) when the motor specifications are not related to suitable prop sizes? Final selection seems to be based on trial and error.
For example, say a 5692 motor from Leopard Hobby. The manufacturer states a power output of 5500 watts. At 50 volt, the amp draw is 110 for 730kv. At 35v the amp draw is 160a and 1090 kv. At 29 volts the amp draw is 180 for a kv of 1340. All these examples will give us a theoretical rpm around 35,000 - 38000 rpm, which even allowing for slippage is still relatively high for "normal" use (not racing). What determines the kv value of a motor?
Of cause one could choose a lower kv motor and then prop up, but other than failure how can one safely achieve a given prop size for a given motor amp/voltage limitations? A prerequisite for this hobby seems to be that one has a degree in electrical engineering.
When would one be drawing the full wattage (power) of the motor - using too high a kv to maximise rpm or using too large a diameter prop? How does one select a suitable esc when a manufacturer lists a lower numerical amperage draw against a max voltage that most would never consider? Does a lower amp draw/higher voltage low kv motor differ in construction (wire diameter,number of windings) to a higher kv motor or is it simply that a lower voltage implies a higher amp draw for a given wattage output?
If one chooses to use 6s packs then the specification amp draw places one with the choice of a minimum 180 amp esc and most likely higher, say a 200, 220 or 240 amp unit. A manufacturer will use the amp draw as simply a product of wattage and voltage, however how does one know what his final amp draw is going to be (other than by failure of the esc) when the motor specifications are not related to suitable prop sizes? Final selection seems to be based on trial and error.
For example, say a 5692 motor from Leopard Hobby. The manufacturer states a power output of 5500 watts. At 50 volt, the amp draw is 110 for 730kv. At 35v the amp draw is 160a and 1090 kv. At 29 volts the amp draw is 180 for a kv of 1340. All these examples will give us a theoretical rpm around 35,000 - 38000 rpm, which even allowing for slippage is still relatively high for "normal" use (not racing). What determines the kv value of a motor?
Of cause one could choose a lower kv motor and then prop up, but other than failure how can one safely achieve a given prop size for a given motor amp/voltage limitations? A prerequisite for this hobby seems to be that one has a degree in electrical engineering.
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