Reddy Watts has given the formula:
(Bat. Mah * 0.06) / run time = Amps
For a two battery setup in series, let's say 2 x 2s (4900 mah each) what mah we use 4900 or 9800?
And if in parallel?
(Bat. Mah * 0.06) / run time = Amps
For a two battery setup in series, let's say 2 x 2s (4900 mah each) what mah we use 4900 or 9800?
And if in parallel?
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